Question

plss answer this question its urgent i have to submit my work tomorrow
the digit at the ten's place of a two digit number is four times that in the unit's place. if the digits are reversed, the new number will be 54 less than the original number. find the original number. check your solution.

Answer 1

let the number be  A B.  ,A and B are single digits.

A = 4 * B.
   So  B cannot be more than  2.  As  4 * 3 = 12 and is not a single digit.
   B = 0, 1, or 2. 
 then  A = 0, 4 or 8.
So the number is  :  00, 41, 82.

reversed number:  00,14, 28.

clearly  82 is the number,  as  82 - 24 = 58.
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another solution:

let the number be :    AB.     A is the tens digit.  B is units digit.
         value of the number =  10 * A  + B
         we are given,  A = 4 * B
           so value =  40 * B + B = 41 B

reversed number =  B A,          its value is :   10 * B + A  =  14 * B

The difference between two numbers = difference between two values
         =>     41 B - 14 B = 54
             =>  B = 2
       and so    A = 4 B = 8

the original number is  82.