Question

plss anyone solve ques 24!!!!!

Answer 1

hi,

·         Since ABCD is a parallelogram,

·         AB = CD ......1

·         BC = AD ......2

·          

·         It can be observed that

·         DR = DS (Tangents on the circle from point D)

·         CR = CQ (Tangents on the circle from point C)

·         BP = BQ (Tangents on the circle from point B)

·         AP = AS (Tangents on the circle from point A)

·         Adding all these equations, we obtain

·         DR + CR + BP + AP = DS + CQ + BQ + AS

·         (DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)

·         CD + AB = AD + BC

·         On putting the values of equations (1) and (2) in this equation, we obtain

·         2AB = 2BC

·         AB = BC .......3

·         Comparing equations (1), (2), and (3), we obtain

·         AB = BC = CD = DA

·         Hence, ABCD is a rhombus.