Question

plss give ans fast..... all ansplz plz plz give fast..... ​

Answer 1

❶❶)

$\huge \tt ☄GIVEN:-$

$\tt ✭AC=BD$

$\huge \tt ⍟ PROVE:-$

$\tt ✬AB = CD$

$\huge \tt ✥SOLUTION:-$

$\tt in \: the \: given \: line \: letBC = x$

$\tt AC = BD = y$

$\tt now \: AB = AC - BC$

$\tt = y - x....(i)$

$\tt again$

$\tt CD = BD - BC$

$\tt = y - x ....(ii)$

$\tt so \: from \: eq(i) \: and \: (ii)$

$\tt AB = CD$

HENCE PROVED.....

❶❷)

$\huge \tt ❂GIVEN:-$

$\tt \: total \: no. \: of \: bags \: is \: 5$

$\huge \tt ✵FIND:-$

$\tt probability \: of \: given \: questions$

$\huge \tt ✮SOLUTION:-$

$\tt ✶no. \: of \: bags \: in \: which \: more \: than \\ \tt 40seeds \: germinated \: out \: of \: 50 \: seeds= 3$

$\tt P(E_1) = \frac{favourable \: outcomes}{total \: outcomes} = \frac{ \cancel 3}{ \cancel6} = 0.6$

$\tt ✶no. \: of \: bags \: in \: which \: 49 \: seeds \: germinated = 0$

$\tt P(E_2) = \frac{favourable \: outcomes}{total \: outcomes} = \frac{ \cancel 0}{ \cancel5} = 0$

$\tt ✶no. \: of \: bags \: in \: which \: more \: than \\ \tt 35 \: seeds \: germinated = 5$

$\tt P(E_3) = \frac{favourable \: outcomes}{total \: outcomes} = \frac{ \cancel 5}{ \cancel5} = 1$