Question

plss give correct ans. ​

Answer 1

Answer:

into x and y and y and b then plus they both answer you will get the answer correct

Answer 2

Answer:

Hey u mate here is your answer..

Explanation:

We have,

(x^2+y^2)(a^2+b^2)=(ax+by)^2

Prove that, \dfrac{x}{a}=\dfrac{y}{b}.

∴ (x^2+y^2)(a^2+b^2)=(ax+by)^2

⇒ x^2(a^2+b^2)+y^2(a^2+b^2)=(ax)^2+(by)^{2} +2(ax)(by)

Using algebraic identity,

(x+y)^{2}=x^{2}+y^{2}+2xy

⇒ x^2a^2+x^2b^2+y^2a^2+y^2b^2=a^2x^2+b^2y^{2} +2abxy

⇒ x^2b^2+y^2a^2=2abxy

⇒ x^2b^2+y^2a^2-2abxy=0

⇒ (xb)^2+(ya)^2-2(xb)(ya)=0

Using algebraic identity,

(x-y)^{2}=x^{2}+y^{2}-2xy

⇒ (xb-ya)^2=0

⇒ xb - ya = 0

⇒ xb = ya

⇒ \dfrac{x}{a}=\dfrac{y}{b}, proved.

Hence, \dfrac{x}{a}=\dfrac{y}{b}, proved.

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