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chirag8874695183:
very easy it will be by congruence in only any two triangle
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Given anglePOQ = 90°
Also, we can say that
angleOPT = 90° and angleOQT = 90° (radius perpendicular to tangent)
Hence all angles are 90° (sum of all angles of quadrilateral is 360°)
Hence it is either a square or a rectangle
But if its a rectangle , adjacent sides cannot be equal. In this case OP = OQ (radius). So adjacent sides are equal.
Hence it is a square. In a square the diagonals bisect each other at 90° (right angles). Hence proved.
Easy-peasy! Hope this helps! :-)
Also, we can say that
angleOPT = 90° and angleOQT = 90° (radius perpendicular to tangent)
Hence all angles are 90° (sum of all angles of quadrilateral is 360°)
Hence it is either a square or a rectangle
But if its a rectangle , adjacent sides cannot be equal. In this case OP = OQ (radius). So adjacent sides are equal.
Hence it is a square. In a square the diagonals bisect each other at 90° (right angles). Hence proved.
Easy-peasy! Hope this helps! :-)
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