Question

plss give me a answer​

Answer 1

Step-by-step explanation:

a) perimeter of square = 4a = 160 cm

a = 40 cm = side of square

b) perimeter of rectangle = 2(l+b) = 52 cm

b = 12 cm = breadth of rectangle

Answer 2

☆ Question 1:

Given:

• Perimeter of square = 160 cm

To find:

• Length of the side of square.

Solution:

We know that,

$\boxed {\mathfrak {\red {Perimeter\ of\ square = 4s}}}$

Where,

s = side of the square

Substitute the values,

160 = 4s

$\sf \dfrac {160}{4} = s$

$\boxed {\bf {\pink {40\ cm = s}}}$

Verification:

Substitute the value of s as 40 in the equation,

160 = 4s

160 = 4×40

160 = 160

LHS = RHS

Hence Verified!

Side of the square:

Side of the square is 40 cm.

___________________________________________________

☆ Question 2:

Given:

• Perimeter of rectangle = 52 cm
• Length of rectangle = 14 cm

To find:

• Breadth of the rectangle.

Solution:

We know that,

$\boxed {\mathfrak {\green {Perimeter\ of\ rectangle = 2(l+b)}}}$

Where,

l = length

b = breadth

Substitute the values,

52 = 2(14+b)

52 = 28+2b

52-28 = 2b

24 = 2b

$\sf \dfrac {24}{2} = b$

$\boxed {\bf {\blue {12\ cm = b}}}$

Verification:

Substitute the values of b in the equation as 12.

52 = 2(14+b)

52 = 2(14+12)

52 = 2×26

52 = 52

LHS = RHS

Hence Verified!

Breadth of the rectangle:

Breadth of the rectangle is 12 cm.