Question

plss guys solve it's urgent​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Given that:-

$\bigstar\sf{A +B = 72}$_____________(1)

$\bigstar \sf{B+C = 65}$_________________(2)

$\bigstar \sf{C+A = 41}$______________________(3)

$\boxed{\bf{A+B+C = ?}}$

Simplifying equation (1), we can say that:-

$\sf{B = 72-A}$

Placing it in equation (2), we get:-

$\sf{(72-A)+C = 65}$

$\longrightarrow \boxed{\sf{72-A+C= 65}}$

Subtracting (1) with (2) we get:-

$\sf{A+B-(B+C) = 72-65}$

$\sf{A+B-B-C = 7}$

$\implies \bf{A-C = 7}$ __________(4)

Now, adding (3) and (4),

$\sf{C+A+A-C = 41+7}$

$\sf{2A = 48}$

$\bigstar \boxed{\tt{A = 24}}$

Placing the values in (1),

$\sf{24+B = 72}$

$\bigstar \boxed{\tt{B = 48}}$

Placing the value of A in (4),

$\sf{24-C = 7}$

$\bigstar \boxed{\tt{C = 17}}$

Adding them , (A+B+C),

$\bigstar \boxed{\boxed{\tt{24+48+17 = 89}}}$ is the answer.