Math, asked by hemarawat370, 10 months ago

Plss gyus tell me were i have done wrong my solution is not coming correct......

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Answered by Anonymous
1

Nothing is wrong in the solution ..xD

Just the thing is, you didn't solve it further. I'll do it for you:

k^2 + 3k - k - 3k = 0 [Your last equation]

=> k^2 - k = 0

=> k(k - 1) = 0

=> k = 0, 1

Thus, the value of k can be either equal to 0, or equal to 1.

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