Plss gyus tell me were is my solution wrong my X is not coming correct....
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Step-by-step explanation:
let tens digit be X and ones digit be y
given,tens digit is equal to three times of ones digit
i.e.x=3y-----------(1)
if 54 is subtracted
to number,digits are reversed
i.e.10x+y-54=10y+X
10x-x-10y+y=o
9x-9y-54=0
9[x-y-6]=0
substitute (1) in this
3y-y-6=0
2y=6
y=3
substitute y=3 in (1)
X=3(3)
x=9
therefore number is 93
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