Question

Plss help as fast as possible.. ❤️​

Answer 1

Answer:

Step-by-step explanation:

a). corresponding triangles are congruent as their sides are congruent to each other (S.S.S postulate)

b).  the angle bounded by two lines perpendicular to each other is always 90 degree. thus, there are right angled triangles

c). AB =  13

  BC = 10

  AD = ?

BD + DC = BC

BC - CD = BD

10 - 5 = 5

BD = 5

pythagoras theorm

AD = (BD)^2 + (AB)^2

AD = (5)^2 + (13)^2

AD = 25 + 169

AD = 194

d).

AREA?

1/2 (BASE) (HEIGHT)

= 1/2 (5)(194)

= 485 m^2

Answer 2

Answer:

a) Yes the triangle ABD and triangle ADC are equal

b) Yes, triangle ABD and ADC are right angled triangls

c)See the step by step explanation

Step-by-step explanation:

If AB= 13cm and BC= 10cm

then AD =

$\sqrt{ {13}^{2} - { \frac{10}{2} }^{2} }$

$\sqrt{169 - 25}$

$\sqrt{144}$

$12$

Then, AD=12