Question

plss help me out...​

Answer 1

Solution=>
sum of zeroes=√2
product of zeroes=-3/2

Therefore, Required polynomial is
x²-sum of zeroes(x)+product=0
x²-√2x+(-3/2)=0
x²-√2x-3/2=0
2x²-2√2x-3/2 (by taking L.C.M)

Therefore, quadratic polynomial is
2$x {}^{2} - 2 \sqrt{2x } - 3 = 0$


To find its zeroes,
2x²-2√2x-3=0
(x-√2)(x+3/2)
x=√2,-3/2
Answer

Answer 2

i hopeit helps .... ..