Plss help to find the answer,urgent
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a.
Area of Triangle ABC = 24 cm²
Area of Triangle ABC = Area of Triangle BMC + Area of Triangle AMB
ATQ
Area of Triangle ABC = 24 cm²
Area of Triangle ABC = Area of Triangle BMC + Area of Triangle AMB
24 cm² = Area of Triangle BMC + 10 cm²
24 cm² - 10 cm = Area of Triangle BMC
14 cm² = Area of Triangle BMC
OR
Area of Triangle BMC = 14 cm²
b.
In Triangle AMD and CMB
DM = MB (Diagonals busect each other)
Angle DMA = Angle CMB (Vertically opp. angles)
CM = MA (Diagonals busect each other)
Therefore,
Triangle AMD is Congruent to Triangle CMB
By CPCT,
Therefore,
Area of Triangle AMD = 12 cm²
Hope it helps you, hv a nyc day
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