Question

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QUADRATIC EQUATION ✔✔

Discuss the nature of Roots of each of the following!

a.). 2x² - 2√6x + 3=0​

Answer 1

Answer:

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Answer 2

Answer:

$\huge{\boxed{\sf{D=0\:ROOTS\:ARE\ :REAL\:AND\:EQUAL}}}$

Step-by-step explanation:

$\huge{\boxed{\sf{SOLUTION-}}}$

$2 {x}^{2} - 2 \sqrt{6} x + 3 = 0 \\ D = {b}^{2} - 4ac \\ D = ({ - 2 \sqrt{6} })^{2} - 4(2 \times 3) \\ D = 24 - 24 \\ D = 0 \\ if \: a ,\: b ,\: ,c \:belongs\: to \: R \:and\: D= 0 \: \\ then \: roots \: are \: real \: and \: equal \\ x = \frac{ - b + \sqrt{d} }{2a} \\ x = \frac{ 2 \sqrt{6} }{2} \\ x = \sqrt{6}$

>>NATURE OF ROOTS DEPENDS ON DISCRIMINANT DENOTED AS (D) .

$\huge{\boxed{\sf{D=0\:ROOTS\:ARE\ :REAL\:AND\:EQUAL}}}$