Question

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Answer 1

Explanation:

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Answer 2

★ Answer :

${3}^{3x - 1} \div 9 = 27$

breaking every term in the power of 3

$\implies \: {3}^{3x - 1} \div {3}^{2} = {3}^{3}$

as,

${x}^{a} \div {x}^{b} = {x}^{a - b}$

so here,

$\implies \: {3}^{3x - 1 - 2} = {3}^{3}$

$\implies \: {3}^{3x - 3} = {3}^{3}$

Comparing powers....

$\implies \: 3x - 3 = 3$

$\implies 3x = 6$

so,

${\huge{\boxed{x=2}}}$