Question

plss solbe this answer
The length of a
of a rectangle is 15cm more
than its width and the perimeter is 150cm.
Find the dimension
the redangle​

Answer 1

$\huge\bold\star\red{Answer}$

Let the breadth=x

the length =x+15

given perimeter= 150

we know

Perimeter of rectangle = 2(l+b)

150 = 2( x+ x+15)

75 = 2x +15

60 = 2x

30=x

therefore breadth = 30 cm

length = 30 +15 = 45 cm

check

check 150 = 2( 45+30)

check 150 = 2( 45+30)150 = 2(75)

150 = 150

LHS=RHS

hence proved......☺

Explaination:

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Answer 2

Step-by-step explanation:

${\red{\underline{\underline{\bold{Given:-}}}}}$

• The length of a rectangle is 15cm more than its width

• The perimeter of the rectangle is 150cm

${\blue{\underline{\underline{\bold{To\:Find:-}}}}}$

• The dimensions of the rectangle ( The length and the width)

${\green{\underline{\underline{\bold{Solution:-}}}}}$

Let the width of the rectangle be xcm

According to the given question:-

The length of the rectangle = (x + 15)cm

The perimeter of rectangle = 2( length + width)

Given,

Perimeter = 150 cm

Therefore:-

$2(x + x + 15) = 150 \\ \\ \implies2(2x + 15) = 150 \\ \\ \implies4x + 30 = 150 \\ \\ \implies4x = 150 - 30 \\ \\ \implies4x = 120 \\ \\ \implies x = \frac{120}{4} = 30$

Hence:-

The width of the rectangle = x = 30cm

The length of the rectangle = x+15 = 30+15 = 45cm

${\</strong><strong>pink</strong><strong>{\underline{\underline{\bold{</strong><strong>Verification</strong><strong>:-}}}}}$

2( length + width) = 150

2( 30+ 45) = 150

2( 75) = 150

150 = 150

L.H.S = R.H.S

Hence Proved