plss solve 12th question on any notebook with stepwise solution...
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Coordinates of vertices B and C are (3,0) and (-3,0) respectively.
AD ⊥ BC and CD = DB = 3
Hence D coincides with the origin.
Since ABC is an equilateral triangle, AB = BC = CA = 6 units
AD ⊥ BC and CD = DB = 3
Hence D coincides with the origin.
Since ABC is an equilateral triangle, AB = BC = CA = 6 units
In right triangle ADB, (Fig. given below)
AB² = AD² + DB² [By Pythagoras theorem]
6² = AD² + 3²
36 = AD² + 9
-AD² = 9 - 36
-AD² = -27
AD = √27
AD = 3√3 units
Hence the coordinates of A are (0, 3√3)
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