plss solve fast this sum. do it in rough copy
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jaslynshawn:
where is point p?
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In ΔADB
∠B + ∠D + ∠BAD = 180° (angle sum property)
60° + 90° + ∠BAD = 180°
∴∠BAD = 30°
Now,
∠BAD + ∠CAD = 30° + 35°
∠BAC = 65° (1)
now,
in ΔAEC
∠EAC + ∠E + ∠ACE = 180° ( ASP)
65° + 90° + ∠ACE = 180°
∴ ∠ACE = 25°
NOW IN ΔAPC
∠PAC= 35° and ∠ACP=25°
∴CP is greater than AP {sides opposite to bigger angles are longer}
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