Question

plss solve it.........​

Answer 1

Answer:

Hence, remainder when x^3 + 1 is divided by x + 1 = 0

Step-by-step explanation:

Given,

Dividend, f(x) = x^3 + 1

Divisor, g(x) = x + 1

To find : Remainder when f(x) is divided by g(x).

Solution :

Since, x + 1 is the divisor.

So by using reminder theorem, we get,

x = -1

By applying the value of x = -1 in f(x) , we get,

=> f(x) = (-1)^3 + 1

=> (-1) + 1 = 0

=> 0

Hence, remainder when x^3 + 1 is divided by x + 1 = 0

'A piece of Supplementary Counsel' :-

• Remainder Theorem = In algebra, the polynomial remainder theorem or little Bézout's theorem is an application of Euclidean division of polynomials. It states that the remainder of the division of a polynomial by a linear polynomial is equal to In particular, is a divisor of if and only if a property known as the factor theorem.

• Factor Theorem = In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial. It is a special case of the polynomial remainder theorem. The factor theorem states that a polynomial has a factor if and only if.

Answer 2

Answer:

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