Math, asked by qwertymouni, 5 months ago

plss solve it guysss...​

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Answered by Anonymous
40

Solution:-

➤ log(y)  =  log_{x}(y)  =  y log(x)

➤ \frac{d}{dx} \times  log(y)  =  \frac{d}{dx}  \times y log(x)

➤ \frac{1}{y}  \times   \frac{dy}{dx}  = y \frac{1}{x} +  log(x)  \frac{dy}{dx}

➤ \frac{dy}{dx} ( \frac{1}{y}  -  log(x) ) =  \frac{y}{x}

➤ \frac{dy}{dx} ( \frac{1 -  log_{y}(x) }{y} )

➤ \frac{y}{x}  =  \frac{dy}{dx} =  \frac{ {y}^{2} }{x(1 -  log_{y}(x)) }

➤ \frac{ {y}^{2} }{(1 -  log(y)) } (Answer)

  • Hope it helps you ✔️

@Fabled

Answered by afdwl
1

Answer:

Step-by-step explanation:

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