plss solve it yrr nnnnnnmmm
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Hey...mate here is yur ans...
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
Soln..➡ Fictitious force on the block opposite to the acceleration of the block.
F = ma = 1 × 5 = 5N
while the limiting friction force
F = =
= 0.6 × 1× 9.8 = 5.88 Newton.
as applied force F lesser than limiting friction force. The block will remain at rest in the truck and the force of friction will be equal to 5N and in the direction of acceleration of the truck.
______________________________
HOPE IT HELPS U✌
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
Soln..➡ Fictitious force on the block opposite to the acceleration of the block.
F = ma = 1 × 5 = 5N
while the limiting friction force
F = =
= 0.6 × 1× 9.8 = 5.88 Newton.
as applied force F lesser than limiting friction force. The block will remain at rest in the truck and the force of friction will be equal to 5N and in the direction of acceleration of the truck.
______________________________
HOPE IT HELPS U✌
Answered by
3
Hope it works for you
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