Plss Solve Qsn 42 ,43.....?
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We can write x²=|x|², so,
x²-3|x|+2=0
|x|²-3|x|+2=0
|x|=1,2
x=±1,±2
x+(1/x) is minimum at x=1 for x>0
x²-3|x|+2=0
|x|²-3|x|+2=0
|x|=1,2
x=±1,±2
x+(1/x) is minimum at x=1 for x>0
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