Math, asked by Anonymous, 10 months ago

Plss solve the 2nd question

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Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
9

\displaystyle\large\underline{\sf\red{Given}}

✭ Sum of the digits of a two digit number is 12

✭ If the digits are reversed then the new number is 54 greater than the original one

\displaystyle\large\underline{\sf\blue{To \ Find}}

◈ The original number?

\displaystyle\large\underline{\sf\gray{Solution}}

Let's assume the numbers to digits to be x & y

  • Original Number = 10x+y
  • On reversing = 10y+x

━━━━━━━━━

\underline{\bigstar\:\textsf{According to the given Question :}}

»» \displaystyle\sf x+y = 12\:\:\: -eq(1)

Also on reversing the digits,

\displaystyle\sf 10x+y+54 = 10y+x

\displaystyle\sf 10x+y-10y+x = -54

\displaystyle\sf 9x-9y = 54

\displaystyle\sf 9(x-y) = 54

\displaystyle\sf x-y = \dfrac{54}{9}

\displaystyle\sf x-y = -6\:\:\: -eq(2)

Adding eq(2) from eq(1)

›› \displaystyle\sf x+y+x-y = 12+(-6)

›› \displaystyle\sf 2x = 6

›› \displaystyle\sf x = \dfrac{6}{2}

›› \displaystyle\sf \orange{x = 3}

Substituting the value of x in eq(1)

\displaystyle\sf x+y = 12

\displaystyle\sf y = 12-3

\displaystyle\sf y = 12-3

\displaystyle\sf \pink{y = 9}

\displaystyle\therefore\:\underline{\sf The \ Number \ will \ be \ 39}

━━━━━━━━━━━━━━━━━━

Answered by HɪɢʜᴇʀKᴜsʜᴀʟBᴏʏSᴜʙs
0

\displaystyle\large\underline{\sf\pink{Given}}

  • ✭Sum of the digits of a two digit number is 12

  • If the digits are reversed then the new number is 54 greater than the original one

\displaystyle\large\underline{\sf\blue{To \ Find}}

  • The original number?

\displaystyle\large\underline{\sf\gray{Solution}}

Let us assume the numbers to digits to be x & y

Original Number = 10x+y

On reversing = 10y+x

━━━━━━━━━

\underline{\bigstar\:\textsf{According to the given Question :}}

»» \displaystyle\sf x+y = 12\:\:\: -eq(1)

Also on reversing the digits,

\displaystyle\sf 10x+y+54 = 10y+x

\displaystyle\sf 10x+y-10y+x = -54

\displaystyle\sf 9x-9y = 54

\displaystyle\sf 9(x-y) = 54

\displaystyle\sf x-y = \dfrac{54}{9}

\displaystyle\sf x-y = -6\:\:\: -eq(2)

Adding eq(2) from eq(1)

›› \displaystyle\sf x+y+x-y = 12+(-6)

›› \displaystyle\sf 2x = 6

›› \displaystyle\sf x = \dfrac{6}{2}

›› \displaystyle\sf \orange{x = 3}

Substituting the value of x in eq(1)

\displaystyle\sf x+y = 12

\displaystyle\sf y = 12-3

\displaystyle\sf y = 12-3

\displaystyle\sf \pink{y = 9}

\displaystyle\therefore\:\underline{\sf The \ Number \ will \ be \ 39}

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