plss solve the question fast it's urgent
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because =180 and sum of afc and aec =180 proved
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Let $ = angle
$ABC = $ ADC = X ($ made by same arc are =)
$BAD = $BCD = Y ( same reason)
we Know ,
$AOC = $2×ABC = $2×ADC
$AOC = 2X
In ∆FDC
$ AFC = $X + $Y ( exterior $ property of ∆)----(1)
IN ∆ CBE
$ E + $Y = $CBE = X ( exterior $ property of ∆)
$E = $X - $Y----(2)
$ AOC = 2X = $X-$Y + $X+$Y (from 1 & 2)
$ABC = $ ADC = X ($ made by same arc are =)
$BAD = $BCD = Y ( same reason)
we Know ,
$AOC = $2×ABC = $2×ADC
$AOC = 2X
In ∆FDC
$ AFC = $X + $Y ( exterior $ property of ∆)----(1)
IN ∆ CBE
$ E + $Y = $CBE = X ( exterior $ property of ∆)
$E = $X - $Y----(2)
$ AOC = 2X = $X-$Y + $X+$Y (from 1 & 2)
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