Question

plss solve this.......

Answer 1

Given 3(log 5 - log 3) - (log 5 - 2 log 6) = 2 - log x.

= > 3 log 5 - 3 log 3 - log 5 + 2 log 6  = 2 - log x

= > 2 log 5 - 3 log 3 + 2 log 6 + log x = 2

= > log x = 2 - 2 log 5 + 3 log 3 - 2 log 6

               = 2 - log(5^2) + log(3^3) - 2 log 6

               = 2 + log(3^3) - log(5^2) - 2 log 6  (log(a - b) = log(a/b))

               = 2 + log(3^3/5^2) - 2 log 6

               = 2 + log(27/25) - 2 log 6

               = 2 + log(27/25) - log(6^2)

               = 2 + log(27/25/6^2)

               = 2 + log(3/100)

               = 2 + log(3) - log(100)

               = 2 + log 3 - 2

               = log 3


= > log x = log 3

=> x = 3.


Hope this helps!