Question

plss solve this ......

Answer 1

in general log(ab)=log a + log b
given log(a+b)=log a+ log b
so ab = a+ b
1 = 1/b+1/a
1-1/b = 1/a
a = b/b-1

Answer 2

We know that log ab = log a + log b

LHS: log(a + b) = log a + log b

RHS = log a + lob gb = log ab

On solving both Equations, we get

log(a + b) = log(ab)

a + b = ab

b = ab - a

b = a(b - 1)

a = b/(b - 1)


Hope this helps!