plss solve this ......
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in general log(ab)=log a + log b
given log(a+b)=log a+ log b
so ab = a+ b
1 = 1/b+1/a
1-1/b = 1/a
a = b/b-1
given log(a+b)=log a+ log b
so ab = a+ b
1 = 1/b+1/a
1-1/b = 1/a
a = b/b-1
siv2:
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wlcm
Answered by
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We know that log ab = log a + log b
LHS: log(a + b) = log a + log b
RHS = log a + lob gb = log ab
On solving both Equations, we get
log(a + b) = log(ab)
a + b = ab
b = ab - a
b = a(b - 1)
a = b/(b - 1)
Hope this helps!
LHS: log(a + b) = log a + log b
RHS = log a + lob gb = log ab
On solving both Equations, we get
log(a + b) = log(ab)
a + b = ab
b = ab - a
b = a(b - 1)
a = b/(b - 1)
Hope this helps!
Thanks for the brainliest khushi
wlcm
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