Math, asked by kumaraddy906078, 3 months ago

plss solve this question ​

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Answered by senboni123456
1

Step-by-step explanation:

We have,

 \frac{( {x}^{2} - x + 1) ({x}^{2} - 4)  }{( {x}^{2}  - 3x + 2)(x + 7)}  \leqslant 0 \\

since, (x² - x + 1) is always positive, so we have the following inequality

 \frac{(x + 2)(x - 2)}{(x - 2)(x - 1)(x + 7)}  \leqslant 0 \\

x \in( - 7 \: to \:  - 2]  \: or \: x \in(1 \: to \: 2)

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