plss solve this question it is urgent
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Heya!!!
Required area = πr² / 2 - ( area of Trangle ACB)
By Pythagoras theorem
( AB ) ² = ( BC )² + ( AC )²
AB = 26cm
r = AB / 2 = 13
Required area = π ( 13 )² / 2 - ( 1 / 2. × 24 × 10 )
265.33 - 120 = 145.33cm²
Hope it helps.
Required area = πr² / 2 - ( area of Trangle ACB)
By Pythagoras theorem
( AB ) ² = ( BC )² + ( AC )²
AB = 26cm
r = AB / 2 = 13
Required area = π ( 13 )² / 2 - ( 1 / 2. × 24 × 10 )
265.33 - 120 = 145.33cm²
Hope it helps.
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3
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