Math, asked by Satyamkumarjmp1999, 7 months ago

plss solve very fast ️​

Attachments:

Answers

Answered by bhanuprakashreddy23
5

Answer:

thank me and mark as brainliest

Step-by-step explanation:

2√3n^2-5n+√3=0

2√3n^2-2n-3n+√3=0

2n(√3n-1)-√3(√3n-1)=0

(2n-√3)(√3n-1)=0

2n-√3=0. ;√3n-1=0

2n=√3. ;√3n=1

n=√3/2. ;n=1/√3

Answered by devanayan2005
0

Answer:

The roots for the equation are √3/2 and 1/√3.

Step-by-step explanation:

2√3n^2 - 5n + √3 = 0

2√3n^2 -2n -3n + √3 =0

2n(√3n-1)-√3(√3n-1)=0

(2n-√3)(√3n-1)=0

2n-√3=0

√3n-1=0

2n=√3

√3n=1

n=√3/2 and n=1/√3

Hope it helps

Similar questions