Math, asked by raghav167, 1 year ago

plss sove it. ..........

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Answers

Answered by āmıt
0
= x^4-216x

=x (x^3-216)

=x [x^3-6^3]

=x (x-6) (x^2+x×6+6^2)

=x (x-6) (x^2+6x+36)

raghav167: wrong
āmıt: how
karla1276: this is the answer x(x−6)(x2+6x+36)
āmıt: yes there will be( x-6)
āmıt: not square of them
karla1276: your answer is correct
raghav167: plss send attachment. i m unable to understand
karla1276: there is no option to answer the question now
Answered by karla1276
1
here is the answer...
this is how I opened x^3-6^3 point 7
hope that helps
Attachments:

raghav167: thanks
karla1276: you are welcome
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