Question

plss tell me the answer​

Answer 1

Step-by-step explanation:

6

6There are several methods to get the answer but here we will discuss best and shortest way. As per the divisibility rule of 11, the difference of sum of the digits at odd places and sum of the digits at even places must be 0, 11, 22, 33…. etc.

6There are several methods to get the answer but here we will discuss best and shortest way. As per the divisibility rule of 11, the difference of sum of the digits at odd places and sum of the digits at even places must be 0, 11, 22, 33…. etc.=> (4+6+3)-(2+5+k)=0/11/22…

6There are several methods to get the answer but here we will discuss best and shortest way. As per the divisibility rule of 11, the difference of sum of the digits at odd places and sum of the digits at even places must be 0, 11, 22, 33…. etc.=> (4+6+3)-(2+5+k)=0/11/22…=> (13)-(7+k)=0 [since 11/22… are not possible]

6There are several methods to get the answer but here we will discuss best and shortest way. As per the divisibility rule of 11, the difference of sum of the digits at odd places and sum of the digits at even places must be 0, 11, 22, 33…. etc.=> (4+6+3)-(2+5+k)=0/11/22…=> (13)-(7+k)=0 [since 11/22… are not possible]=> 13-7-k=0

6There are several methods to get the answer but here we will discuss best and shortest way. As per the divisibility rule of 11, the difference of sum of the digits at odd places and sum of the digits at even places must be 0, 11, 22, 33…. etc.=> (4+6+3)-(2+5+k)=0/11/22…=> (13)-(7+k)=0 [since 11/22… are not possible]=> 13-7-k=0=> k=6

6There are several methods to get the answer but here we will discuss best and shortest way. As per the divisibility rule of 11, the difference of sum of the digits at odd places and sum of the digits at even places must be 0, 11, 22, 33…. etc.=> (4+6+3)-(2+5+k)=0/11/22…=> (13)-(7+k)=0 [since 11/22… are not possible]=> 13-7-k=0=> k=6So option (d) is right answer.