Question

plss tell the answer​

Answer 1

Answer:

logblogc

(loga)

2

+

logalogc

(logb)

2

+

logalogb

(logc)

2

=3

⇒(loga)

3

+(logb)

3

+(logc)

3

−3logalogblogc=0

⇒loga+logb+logc=0(asa,b.c,aredistinct)

⇒logabc=0

⇒abc=1