Question

plss this tooo ....... to score full marks

Answer 1

Hello Mate!

Take Your solution in image

Have a Good Day ahead!

Answer 2

$Given : x = \frac{1}{2 - \sqrt{3} }$

On rationalizing, we get

$\frac{1(2 + \sqrt{3} }{(2 - \sqrt{3})(2 + \sqrt{3}) }$

$\frac{(2 + \sqrt{3}) }{(2)^2 - ( \sqrt{3})^2 }$

$= \frac{2 + \sqrt{3} }{4 - 3}$

$\frac{2 + \sqrt{3} }{1}$

$2 + \sqrt{3}$


Now,


x^3 - 2x^2 - 7x + 5

$= (2 + \sqrt{3} )^3 - 2(2 + \sqrt{3} )^2 - 7(2 + \sqrt{3} ) + 5$

$15 \sqrt{3} + 26 - 8 \sqrt{3} - 14 - 7(2 + \sqrt{3} ) + 5$

$= 15 \sqrt{3} + 26 - 8 \sqrt{3} - 14 - 14 - 7 \sqrt{3} + 5$

$= 5 - 14 - 14 + 26$

$= 3.$



Hope this helps!