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We know,sum of all three angles of a triangle = 360°
Let ∠PRQ be x°.
So,∠SPR + ∠PQT + ∠PRQ = 360°
⇒ 135°+110°+x°=360°
⇒ x°=(360-245)°
⇒ x°=115°
Thus, ∠PRQ = 115°(ANS)
Let ∠PRQ be x°.
So,∠SPR + ∠PQT + ∠PRQ = 360°
⇒ 135°+110°+x°=360°
⇒ x°=(360-245)°
⇒ x°=115°
Thus, ∠PRQ = 115°(ANS)
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