Chemistry, asked by denamoscr7, 9 months ago

plsss answer all plsss​

Attachments:

Answers

Answered by Mysterioushine
6

 \huge \red { \underline{ \underline {Answer : - }}}

Option(C) ic correctly balanced equation of the given reaction.

 \huge \green{ \underline{ \underline{Explanation : - }}}

★ Consider option(A) ,

\setlength{\unitlength}{1 cm}\begin{picture}(0,0) \thicklines \put(0,0){ \vector(2, 0){2.3}}\put(  0.1,0.3){ $\large{ \boxed{sunlight}}$}\put( - 1.5,0){ $\large{3AgNO_{3}}$}\put(2.5,0){ $\large{3Ag + 3 NO_2 + O_2}$}\end{picture}

Before Reaction ,

Number of atoms of Ag = 3

Number of atoms of N = 3

Number of atoms of O = (3)(3) = 9

After reaction ,

Number of atoms of Ag = 3

Number of atoms of N = 3

Number of atoms of O = 3(2) + 2 = 8

Here Number of atoms of O is not equal before and after the chemical reaction . Hence ,this equation is not balanced

★Consider option(B) ,

\rm{2AgNO_{3}\xrightarrow{ \boxed{Sunlight}}{2Ag} + {2NO_2} + {2O_2}}

Before Reaction ,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = 2(3) = 6

After reaction ,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = (2)(2) + (2)(2) = 8

Here Number of atoms of O is not equal before and after the chemical reaction . Hence , This equation is not balanced

★ Consider option(C),

\setlength{\unitlength}{1 cm}\begin{picture}(0,0) \thicklines \put(0,0){ \vector(2, 0){2.3}}\put(  0.1,0.3){ $\large{ \boxed{sunlight}}$}\put( - 1.5,0){ $\large{2AgNO_{3}}$}\put(2.5,0){ $\large{2Ag + 2NO_2 + O_2}$}\end{picture}

Before reaction ,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = 2(3) = 6

After Reaction,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = 2(2) + 2 = 6

Here Number of atoms are equal before and after the reaction. Hence , This equation is balanced

∴ Option (C) is the required answer

Answered by abdulrubfaheemi
3

Answer:

\huge \red { \underline{ \underline {Answer : - }}}

Answer:−

Option(C) ic correctly balanced equation of the given reaction.

\huge \green{ \underline{ \underline{Explanation : - }}}

Explanation:−

★ Consider option(A) ,

\setlength{\unitlength}{1 cm}\begin{picture}(0,0) \thicklines \put(0,0){ \vector(2, 0){2.3}}\put( 0.1,0.3){ $\large{ \boxed{sunlight}}$}\put( - 1.5,0){ $\large{3AgNO_{3}}$}\put(2.5,0){ $\large{3Ag + 3 NO_2 + O_2}$}\end{picture}

Before Reaction ,

Number of atoms of Ag = 3

Number of atoms of N = 3

Number of atoms of O = (3)(3) = 9

After reaction ,

Number of atoms of Ag = 3

Number of atoms of N = 3

Number of atoms of O = 3(2) + 2 = 8

Here Number of atoms of O is not equal before and after the chemical reaction . Hence ,this equation is not balanced

★Consider option(B) ,

\rm{2AgNO_{3}\xrightarrow{ \boxed{Sunlight}}{2Ag} + {2NO_2} + {2O_2}}2AgNO

3

Sunlight

2Ag+2NO

2

+2O

2

Before Reaction ,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = 2(3) = 6

After reaction ,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = (2)(2) + (2)(2) = 8

Here Number of atoms of O is not equal before and after the chemical reaction . Hence , This equation is not balanced

★ Consider option(C),

\setlength{\unitlength}{1 cm}\begin{picture}(0,0) \thicklines \put(0,0){ \vector(2, 0){2.3}}\put( 0.1,0.3){ $\large{ \boxed{sunlight}}$}\put( - 1.5,0){ $\large{2AgNO_{3}}$}\put(2.5,0){ $\large{2Ag + 2NO_2 + O_2}$}\end{picture}

Before reaction ,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = 2(3) = 6

After Reaction,

Number of atoms of Ag = 2

Number of atoms of N = 2

Number of atoms of O = 2(2) + 2 = 6

Here Number of atoms are equal before and after the reaction. Hence , This equation is balanced

∴ Option (C) is the required answer

Similar questions