Question

plsss AnsWer this question :)​

Answer 1

Answer:

$\sf \dfrac{{x}^{a \: (b - c)} }{ {x}^{b \: (a - c)} } \: \div \: \bigg \lgroup \dfrac{ {x}^{b} }{ {x}^{a} } \bigg \rgroup^{c} \: = \: 1$

Now,

$\sf \dfrac{{x}^{ab \: - \: ac} }{ {x}^{ba \: - \: b c} } \: \div \: \bigg \lgroup \dfrac{ ({x}^{b} )}{( {x}^{a}) } \bigg \rgroup^{c} \: = \: 1$

$\sf \dfrac{{x}^{ab \: - \: ac} }{ {x}^{ba \: - \: b c} } \: \div \: \dfrac{ {x}^{bc} }{{x}^{ac} } \: = \: 1$

We know that,

When sign change from division to multiplication we should do reciprocal of next number.

Therefore we get,

$\sf \dfrac{{x}^{ab \: - \: ac} }{ {x}^{ba \: - \: b c} } \: \times \: \dfrac{ {x}^{ac} }{{x}^{bc} } \: = \: 1$

$\sf \dfrac{{x}^{ab \: - \: \cancel {ac }\: + \: \cancel{ac}} }{ {x}^{ba \: - \: \cancel{ b c} \: + \: \cancel{bc}} } \: = \: 1$

$\sf \dfrac{{x} \: ^{ \cancel{ab}} }{ {x} \: ^{\cancel{ba}} } \: = \: 1$

$\bigstar \: \: \underline{ \boxed{\sf x \: = \: 1}} \: \: \bigstar$

$\huge\bf \dag \: \gray{RHS = LHS} \: \dag$

$\large \boxed{\boxed{\star \: \tt Hence, Verified \: \star}}$

Answer 2

Answer:

{x^ab-ac)/x^ab - bc} / x^bc/x^ac

x^ab-ac - ab-bc / x^bc - ac

(-ab and +ab gets cancelled)

[a^0 = 1 ; a^m/a^n = a^m-n] i have used these two formulaes all over the answer........

x^-ac-bc  / x^bc - ac

x^-ac+ac+bc-bc

x^0 = 1

hope it helps!

plz mark as brainliest !

Step-by-step explanation: