Math, asked by mrajnik20, 5 months ago

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Answered by amtulmusawar346
1

if the perimeter of right isosceles triangle is (6+32square)cm,then area of triangle is

a+a+√2a=(6+3√2m)

a(2+√2)=3(2+√2)m

a=3m

hence area of a triangle

1/2× base× height

1/2×3×3=4.5msquare

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