plsss can anyone solve this ques plssssss
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Answered by
2
let y = √61(√61(√61...…...)
here term in ∞
y =√61(√61(√61....)
here after first term all are repeated again and again
so, we can say then after first √61 term =y
e.g y =√(61y)
now,
y =√(6y)
y² =61y
y² -61y =0
y(y -61) =0
y =0, 6 1
but y ≠ 0 so, y = 61 ( answer)
here term in ∞
y =√61(√61(√61....)
here after first term all are repeated again and again
so, we can say then after first √61 term =y
e.g y =√(61y)
now,
y =√(6y)
y² =61y
y² -61y =0
y(y -61) =0
y =0, 6 1
but y ≠ 0 so, y = 61 ( answer)
abhi178:
is this correct answer ???
Answered by
0
Answer to this question is 61 itself
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