Plsss factorise : a⁴-a.
answer is a(a-1)(a²+a+1)
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a^4 - a
= a ( a^3 - 1)
= a [ (a)^3 - (1)^3]
= a (a - 1)(a^2 + a + 1)
[ x^3 - y^3 = (x-y) (x^2 + y^2 +ab]
= a ( a^3 - 1)
= a [ (a)^3 - (1)^3]
= a (a - 1)(a^2 + a + 1)
[ x^3 - y^3 = (x-y) (x^2 + y^2 +ab]
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