Math, asked by Anonymous, 1 month ago

plsss help both are separate Q and plss don't scam

class 7 ncert plsss​

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Answered by Anonymous
17

{\pmb{\sf{\underline{Question \: 9^{th}}}}}

Question: In a complete examination consisting of 100 questions every correct answer get 3 marks and every incorrect answer get -1 marks. If a condidate has given 60 correct answers and 40 incorrect answers, what it their score?

Given that:

  • Total questions = 100
  • Correct answer carry 3 marks
  • Incorrect answer carry -1 marks
  • Given correct answer = 60
  • Given incorrect answer = 40

To find:

  • Score of candidate

Solution:

  • Score of candidate

Full Solution:

~ As it's given that

  • Total questions = 100
  • Correct answer carry 3 marks
  • Given correct answer = 60

~ Henceforth,

▶️ Marks (added+) for correct answer = 60 × 3

▶️ Marks (added+) for correct answer = 180

~ Now as it's given that

  • Total questions = 100
  • Given incorrect answer = 40
  • Incorrect answer carry -1 marks

~ Henceforth,

▶️ Marks (deducted -) for a incorrect answer = -1

▶️ Marks (deducted -) for 40 incorrect answer = 40 × -1

▶️ Marks (deducted -) for 40 incorrect answer = -40

~ Now total marks

▶️ Marks (added+) for correct answer = 180

▶️ Marks (deducted -) for 40 incorrect answer = -40

▶️ Henceforth, total marks are Marks (added+) for correct answer + (-Marks (deducted -) for 40 incorrect answer)

▶️ Henceforth, total marks are 180 + (-40)

▶️ Henceforth, total marks are 180 - 40

▶️ Henceforth, total marks are 140

Henceforth, their score is 140 marks.

{\pmb{\sf{\underline{Question \: 10^{th}}}}}

Question: Find the value of the expression given below.

{\underline{\boxed{\sf{\quad \Bigg(\dfrac{9}{2} \div \dfrac{17}{4} \Bigg)\;  - \;\Bigg (\dfrac{16}{5} \times  - \dfrac{25}{68} \Bigg)\quad}}}}

Full Solution:

{\underline{\boxed{\sf{\Bigg(\dfrac{9}{2} \div \dfrac{17}{4} \Bigg)\;  - \;\Bigg (\dfrac{16}{5} \times  - \dfrac{25}{68} \Bigg)}}}} \\ \\ :\implies \sf \Bigg(\dfrac{9}{2} \div \dfrac{17}{4} \Bigg)\;  - \;\Bigg (\dfrac{16}{5} \times  - \dfrac{25}{68} \Bigg) \\ \\ :\implies \sf \Bigg(\dfrac{9}{2} \times \dfrac{4}{17} \Bigg)\;  - \;\Bigg (\dfrac{16}{5} \times  - \dfrac{25}{68} \Bigg) \\ \\ :\implies \sf 9 \times \dfrac{2}{17}- \;\Bigg (\dfrac{16}{5} \times  - \dfrac{25}{68} \Bigg)

:\implies \sf \: \dfrac{18}{17} - \Bigg(16 \times \dfrac{-5}{68}\Bigg)

{\sf{:\implies \dfrac{18}{17}  + </p><p> \dfrac {80}{68}}} \\ \\ {\sf{:\implies \dfrac{18}{17} +  \dfrac{40}{34}}} \\ \\ {\sf{:\implies \dfrac{18}{17}  + </p><p>\dfrac{20}{17}}} \\ \\ {\sf{:\implies \dfrac{38}{17}}}

Henceforth, solution is 38/17

  • Sorry for the LaTeX mistakes in some steps, actually I tried to correct it several times but due to error correct LaTeX coming wrong. Hope you understand me! But those LaTeX which are coming wrong, kindly see from attachment the last steps of Question 10th.
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