plsss help guys........
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Let the width be a
Length = a+3
According to question
Area = Perimeter
=> a(a+3) = 2(a+a+3)
=> a^2 + 3a = 4a +6
=> a^2 - a - 6= 0
=> a^2 - 3a +2a - 6 = 0
=> a(a-3) +2(a-3) = 0
=> (a-3)(a+2) = 0
a = 3 and - 2
Length can't be negative
So, a=3
Length = 6 m
Width = 3 m
Length = a+3
According to question
Area = Perimeter
=> a(a+3) = 2(a+a+3)
=> a^2 + 3a = 4a +6
=> a^2 - a - 6= 0
=> a^2 - 3a +2a - 6 = 0
=> a(a-3) +2(a-3) = 0
=> (a-3)(a+2) = 0
a = 3 and - 2
Length can't be negative
So, a=3
Length = 6 m
Width = 3 m
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