Question

plsss hlep me the ansrr is 26...

7th one

Answer 1

Let units's digit be x 
Since the product of its digits is 12, its ten's digit = 12/x 

then, number = $10 * (\frac{12}{x})+ x$

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When 36 is added, digits are interchanged, number becomes $10x + \frac{12}{x}$

⇒ 10x + $\frac{12}{x}$ = $(10 * \frac{12}{x} + x) + 36$

⇒ 10x + $\frac{12}{x}$ = $\frac{120}{x} + x + 36$

⇒ 10x² + 12 = 120 + x² + 36x

⇒ 10x² - x² - 36x + 12 - 120 = 0 

⇒ 9x² - 36x - 108 = 0 

⇒ x² - 4x - 12= 0

⇒ x² - (6 - 2)x - 12 = 0 

⇒ x²  - 6x + 2x - 12 =  0

⇒ x(x - 6) + 2(x  - 6) = 0 

⇒ (x - 6)(x + 2) = 0 

               By Zero product rule

x = 6   or  x = -2


Taking +ve , x = 6 

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unit's digit = 6 

ten's digit = 12/x = 12/6 = 2 


number = 26 


i hope this will help you


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