Question

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Answer 1

Answer:

1)(sec3∅-2)(√3tan2∅-1)=0

sec3∅-2=0 & √3tan2∅-1=0

sec3∅=2 tan2∅=1/√3

sec3∅= sec60 tan2∅=tan30

3∅=60 2∅= 30

∅=60/3 = 20° ∅=30/2 = 15°

therefore ∅ = 15° and 30°

2) given:-

(sinAcosB + cosAsinB)² + (cosAcosB - sinAsinB)²

=>(sin(A+B))² + (cos(A+B))²

=>(sin(60+30))² + (cos(60+30))²

=>sin²90 + cos²90

=>1² + 0

=>1

3) sin30 - sin90 +2cos0

tan30×tan60

=> 1/2 - 1 +2×1

1/√3 ×√3

=> 1/2 - 1 +2

1

=> 1/2+1

=> 3/2