plsss solve ques no 3. hurry experts
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let the speed be x km/hr
and time taken be y
as per question
{x+10}{y-2}=. xy
(x-10)(y+3)=. xy
so
xy +10y-2x-20=xy-10y+3x-30
20y+10=5x
4y+2=x
put the value of x in any equation u will get a quadratic equation solve it neglect the negative the another will be ur answers
i am remaining the others for you
and time taken be y
as per question
{x+10}{y-2}=. xy
(x-10)(y+3)=. xy
so
xy +10y-2x-20=xy-10y+3x-30
20y+10=5x
4y+2=x
put the value of x in any equation u will get a quadratic equation solve it neglect the negative the another will be ur answers
i am remaining the others for you
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