plsss urgent..... solve it plzzz 11 the one plzz
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Given α and 1/α are the zeroes of 4x² - 2x + ( k - 4 ).
Here,
Coefficient of x² = 4
Coefficient of x = -2
Constant term = k - 4.
We know that,
⇒ Product of zeroes = Constant term ÷ Coefficient of x²
⇒ α ( 1/α ) = ( k - 4 ) ÷ 4
⇒ 1 = ( k - 4 ) ÷ 4
⇒ ( k- 4 ) = 4
⇒ k = 4 + 4
∴ k = 8.
Hope it helps !!
Given α and 1/α are the zeroes of 4x² - 2x + ( k - 4 ).
Here,
Coefficient of x² = 4
Coefficient of x = -2
Constant term = k - 4.
We know that,
⇒ Product of zeroes = Constant term ÷ Coefficient of x²
⇒ α ( 1/α ) = ( k - 4 ) ÷ 4
⇒ 1 = ( k - 4 ) ÷ 4
⇒ ( k- 4 ) = 4
⇒ k = 4 + 4
∴ k = 8.
Hope it helps !!
Answered by
1
The value of k is 8..........................
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