Question

plssss...answer for this​

Answer 1

Answer:

Step-by-step explanation:

He mate!!

AB=AC(GIVEN)

ANGLE B=ANGLE C(opposite angles r equal as opposite sides r equal)

In ∆BMP and ∆CNP

ANGLE B=ANGLE C(just proved)

Angle M= Angle N(90°)

∆BMP ~∆ CNP

BP/MP=CP/NP

BP.NP=MP.CP

HENCE PROVED

Answer 2

In triangle ABC

Given:

AB=AC

PM perpendicular to AB

PN perpendicular to AC

To prove: MP. CP = NC. BP

angle BMP = angle CNP (each of 90degree)

angle B = angle C (opposite angles of equal sides)

By AA Similarity BMP~CNP

$\dfrac{MB} {NC}$ = $\dfrac{BP} {CP}$ = $\dfrac{MP} {NP}$

Thus , MP. CP = NC. BP

HENCE PROVED