plssss...answer for this
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Step-by-step explanation:
He mate!!
AB=AC(GIVEN)
ANGLE B=ANGLE C(opposite angles r equal as opposite sides r equal)
In ∆BMP and ∆CNP
ANGLE B=ANGLE C(just proved)
Angle M= Angle N(90°)
∆BMP ~∆ CNP
BP/MP=CP/NP
BP.NP=MP.CP
HENCE PROVED
yashwanth12312:
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Answered by
1
In triangle ABC
Given:
AB=AC
PM perpendicular to AB
PN perpendicular to AC
To prove: MP. CP = NC. BP
angle BMP = angle CNP (each of 90degree)
angle B = angle C (opposite angles of equal sides)
By AA Similarity BMP~CNP
=
= 
Thus , MP. CP = NC. BP
HENCE PROVED
Given:
AB=AC
PM perpendicular to AB
PN perpendicular to AC
To prove: MP. CP = NC. BP
angle BMP = angle CNP (each of 90degree)
angle B = angle C (opposite angles of equal sides)
By AA Similarity BMP~CNP
Thus , MP. CP = NC. BP
HENCE PROVED
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