Question

plssss help chahiye ☹️☹️​

Answer 1

Answer:

Step-by-step explanation:

As tangents from same external point are equal

therefore AF = AE, BF = BD, CD = CE

therefore AF+BD+CE=AE+BF+CD

perimeter of ∆ABC = AB + BC + CA

= AF + AE + BD + BF + CD + CE

therefore ½ perimeter = AF+BD+CE = AE+BF+CD