plssss help chahiye ☹️☹️
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Step-by-step explanation:
As tangents from same external point are equal
therefore AF = AE, BF = BD, CD = CE
therefore AF+BD+CE=AE+BF+CD
perimeter of ∆ABC = AB + BC + CA
= AF + AE + BD + BF + CD + CE
therefore ½ perimeter = AF+BD+CE = AE+BF+CD
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