Question

Plssss helppppppppppppp

Answer 1

Step-by-step explanation:

here is ur required answer!!!!✌

Answer 2

Step-by-step explanation:

Given, Angle N = tetha and angle M = 90°.

LN = 25unit and MN = 24.

PROVE THAT = sin^2tetha + cos^2tetha = 1.

TP PROOF:-

Now in ∆LMN, By Pythagoras theorem,,

LM^2 + MN^2 = LN^2.

; LM^2 + (24)^2 = (25)^2.

; LM^2 + 576 = 625.

; LM^2 = 625 - 576.

; LM^2 = 49.

; LM = +7 or -7 unit.

but a side never be a negative so,, we take 7unit in the length LM.

LETS TAKE FROM LHS,,

SIN^2TETHA + COS^2

; (PERPENDICULAR/HYPOTENUSE)^2 + (BASE/HYPOTENUSE)^2.

; (7/25)^2 + (24/25)^2

; (49/625) + (576/625)

NOW, BY DOING LCM THE FRACTION WE GET,,

; (49 + 576/625)

; (625/625)

; 1.. = RHS (HENCE PROVED)..

HOPE IT WILL BE HELPFUL!!!...