Question

plssss I will mark u as brainliest ​

Answer 1

Answer: option 1

Step-by-step explanation:

b^ 2.(a ^2 cos^ 2 theta)+a^2(b^2sin^2 theta)

b^2 a^2(sin^2 theta+cos^2 theta)

a^2 b^2(1)

a^2 b^2

Answer 2

Answer:

b^2 x^2+a^2 y^2.in this equation we substitute the x and y values

hence it becomes b^2(acos\theta)^2+a^2(ysin\theta)^2

=b^2a^2cos^2\theta+a^2b^2sin^2\theta

=a^2 b^2 cos^2\theta+a^2 b^2 sin^2\theta

=a^2 b^2 (cos^\theta+sin^2\theta)

=a^2 b^2 (1)as cos^2\theta+sin^2\theta=1

=a^2 b^2 is the answer

hope it helps u

n mark as brainliest answer n follow plz