Question

Plssss sloveeeee thiss queee ​

Answer 1

$\frac{1}{ \sqrt{3} - \sqrt{2} } = \frac{1( \sqrt{3} + \sqrt{2} ) }{ \sqrt{3} - \sqrt{2} + ( \sqrt{3}+ \sqrt{2})}= \frac{ \sqrt{3} + \sqrt{2} }{( { \sqrt{3} })^{2} - ({ \sqrt{2} })^{2} } = \frac{ \sqrt{3} + \sqrt{2} }{3 - 2} = \sqrt{3} + \sqrt{2}$

hope it helps

thank you

answer- √3+√2

Answer 2

${\large{\bf{\red{\underline{Given :}}}}}$

Rationalize the denominator of :

${\sf{ \frac{1}{ \sqrt{3} - \sqrt{2} } }}$

${\large{\bf{\blue{\bf{\underline{Solution :}}}}}}$

${\bf{ \frac{1}{ \sqrt{3} - \sqrt{2} } }}$

${\mapsto{\sf{ \frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } }}}$

${\mapsto{\sf{ \frac{ \sqrt{3} + \sqrt{2} }{ (\sqrt{ {3}^{2} } ) - (\sqrt{ {2}^{2} }) } }}}$

${\mapsto{\sf{ \frac{\sqrt{3} + \sqrt{2}}{3 - 2} }}}$

${\mapsto{\sf{ \frac{ \sqrt{3} + \sqrt{2} }{1} }}}$

${\large{\purple{\longrightarrow{\underline{\boxed{\bf{ \sqrt{3} + \sqrt{2} }}}}}}}$

${\large{\maltese{\bf{So,}}}}$

The answer is √3 + √2 .

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