Question

plssss tell guys ........I want answer

Answer 1

Done it was easy......

Answer 2

$= \sec( \alpha ) (1 - \sin( \alpha ))( \sec( \alpha ) + \tan( \alpha ))$
$= ( \sec( \alpha ) - \tan( \alpha ) )( \sec( \alpha ) + \tan( \alpha ) )$
$= \sec( \alpha ) ^{2} - \tan( \alpha ) {}^{2}$
$= 1$
Hence proved ...